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 on: January 30, 2011, 12:16:55 AM 
Started by ijdownie - Last post by ijdownie
Youíre right; there is a bug in the figure. As depicted it shows IPG binary values of 1 and 2 which translates to levels 8 and 4 (bit confusing but have a look at the table on pg28).

What I really should do is move the bits to depict 2 and 4, which is IPG level 4 and 2.

The reason for this confusing mapping of IPG level to bit pattern is that straight binary values donít work. Eg

2 = 0100 (LSB on left and transmitted first)

8 = 0001

Even though level 2 has priority over level 8 the level 2 node it would drop out at bit 2 because the 8 has a 0 at that position.

 on: January 30, 2011, 12:01:46 AM 
Started by ijdownie - Last post by ijdownie
Assuming high level = logic 1 then the first frame is a 1 not 2 and the error (if there is one ) is propagated in the following lines?

The top line should be IPG = 1 RPM = X, and the following lines IPG =  2 and RPM = 6 then IPG = 2 and RPM = C.

 on: January 29, 2011, 11:40:22 PM 
Started by Graynomad - Last post by Graynomad
I've decided to use RS-485 for the physical layer, in preference to LIN.

Why? Mostly because the network was originally designed for vehicles and now I also see it as being used in light-weight process and building control. And RS-485 is pretty much the standard in that field.

This means that the cable has to be 4-core.

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